8z^2-3z-1=0

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Solution for 8z^2-3z-1=0 equation: 



8z^2-3z-1=0

a = 8; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·8·(-1)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{41}}{2*8}=\frac{3-\sqrt{41}}{16}
$


$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{41}}{2*8}=\frac{3+\sqrt{41}}{16}
$

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